Diffusion
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Describe the composition of the cell membrane and how it acts as a semipermeable membrane barrier.
Discuss diffusion in the context of different cellular processes.
Describe the importance of a high SA : V ratio, in terms of cell processes.
aerobic respiration: Enzyme controlled process which requires oxygen to produce 38 ATP from the breakdown of glucose.
cell membrane: Semipermeable barrier surrounding the cytoplasm of a cell.Â
channel proteins: Transmembrane protein that is open to both ends.Â
concentration gradient: When a solute is more concentrated in one area compared to another.Â
diffusion: Passive movement of molecules down a concentration gradient.Â
facilitated diffusion: Transport of substances across a membrane from an area of higher concentration to an area of lower concentration by means of a transmembrane protein.Â
passive transport: Ratio of the cell’s surface area and its volume.Â
photosynthesis: Enzyme-controlled process occurring in plants that use energy from sunlight to combine carbon dioxide and hydrogen to produce glucose.
SA : V ratio: Ratio of the cell’s surface area and its volume.
semi-permeable: Ability of cell membranes to allow some substances to pass it but not others.Â
surface area: Total area occupied by the surface of an object.Â
volume: Amount of space in a 3D object.Â
Diffusion is the movement of molecules from an area of high concentrations to an area of low concentrations (so they are moving down a concentration gradient) until they are equally distributed. Diffusion is a form of passive transport, because it does not require energy in the form of ATP.Â
The difference in concentration between the area of high concentration and the area of low concentration is called the concentration gradient. Diffusion doesn’t require energy because it is driven by this concentration gradient.
A concentration gradient only exists until the molecules are evenly distributed on both sides of the cell membrane. So the concentration gradient is directly proportional to the rate of diffusion.
Oxygen concentration is lower in the muscle cells than in the bloodstream because that is where it is being used. So oxygen diffuses from the bloodstream to the muscle cell.
Carbon dioxide concentration is higher in the muscle cells than in the bloodstream because that is where it is being produced. So carbon dioxide diffuses from the muscle cell to the blood stream.
Carbon dioxide concentration is lower in the leaf cells than in the air because that’s where it is being used up.
Therefore, carbon dioxide diffuses from the air into the leaf (via the stomata).
FACILITATED DIFFUSION, which is the movement of molecules from an area of high concentration to an area of low concentration (down a concentration gradient) through CHANNEL or CARRIER PROTEIN in the CELL MEMBRANE.Â
Its only difference from simple diffusion is that these molecules are unable to diffuse through a cell membrane without the help of their specific carrier protein or protein channel.
Channel and carrier proteins help the diffusion of molecules, such as:
Glucose and amino acids (too large; carrier protein)
Amino acids (some are polar/charged; carrier protein)
Ions (charged; carrier protein)
Bulk flow of water (polar; channel called ‘aquaporin’)
Without aquaporins, water takes a long time to diffuse across the cell membrane.Â
Simulation 1
Explore how molecules can cross a cell membrane and learn about the nature of their movement. Set up the model with high oxygen and low carbon dioxide outside the cell and low oxygen and high carbon dioxide inside the cell.Â
There are many different factors that can affect the rate of DIFFUSION. We will focus a little on temperature, but the most important factor is SURFACE AREA TO VOLUME RATIO (SA : V).
Molecules will diffuse quicker at higher temperatures than at lower temperatures, because increasing the temperature causes the molecules to move faster.Â
Simulation 2: If you place a drop of food colouring into a glass of water, eventually the entire glass is coloured evenly with that dye. Use this model to observe how food colouring diffuses throughout the water.Â
Simulation 3: Observe the model of diffusion below. Notice the position of blue, green, and white particles. In this simplified model, the blue molecules represent perfume molecules, and the white and green molecules represent the nitrogen and oxygen molecules in the air.Â
When a cell grows, the contents of the cell (its volume) increases at a much greater rate than the CELL MEMBRANE (its SURFACE AREA). This is because the surface area increases by a square factor (cm^2) and the VOLUME increases by a cube factor (cm^3).Â
So we say that as the cell grows larger, the SURFACE AREA TO VOLUME RATIO (SA : V) decreases.Â
Because the SA : V ratio plays a vital role in the efficiency of DIFFUSION, cells are dependent on an optimal SA : V ratio to function properly.
If cells get too big, there is comparatively less membrane per volume available for essential molecules such as oxygen to diffuse through and more cell contents that require these molecules in order to function. So diffusion is less efficient for larger cells because essential molecules will not be able to reach the centre of the cell fast enough. The cell that’s too large will also be overloaded with toxic waste products like carbon dioxide in plant cells because waste molecules are unable to diffuse out of the cell quickly enough.Â
Therefore, when a cell gets too large, the cell will divide to keep high surface area to volume ratio.
The cubes in the diagram above represent a cell. The larger 2 cm cube represents a large cell above has a much lower surface area to volume ratio than the small 1 cm cube which represents a small cell.
Different cells have developed different adaptations to increase their surface area to volume ratio. The most common adaptation are tiny hair-like projections called MICROVILLI.
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